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Grade 7Electromagnetic Induction

An elevator descends into a mine shaft at the rat

An elevator descends into a mine shaft at the rate of 6 m/min. The descents starts from 10 m  above sea level

(i)Where will it reach 20 minute?

(ii)How long will it take to reach a depth of -350m?

Profile image of Sonam Sharma
5 Months agoGrade 7
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1 Answer

Profile image of Askiitians Tutor Team

Askiitians Tutor Team

ApprovedApproved Tutor Answer1 Month ago

To solve the problems related to the elevator's descent, we need to use the rate of descent and the starting point.

Calculating the Position After 20 Minutes

The elevator descends at a rate of 6 meters per minute. To find out how far it descends in 20 minutes, we can use the formula:

  • Distance = Rate × Time

Substituting the values:

  • Distance = 6 m/min × 20 min = 120 m

Starting from 10 meters above sea level:

  • Final position = Starting position - Distance descended
  • Final position = 10 m - 120 m = -110 m

After 20 minutes, the elevator will reach a depth of -110 meters.

Time to Reach a Depth of -350 Meters

Next, we need to determine how long it will take to reach a depth of -350 meters. We can find the total distance to descend from the starting point:

  • Total distance = Starting position - Target depth
  • Total distance = 10 m - (-350 m) = 10 m + 350 m = 360 m

Now, we can calculate the time required to descend this distance:

  • Time = Distance ÷ Rate
  • Time = 360 m ÷ 6 m/min = 60 minutes

It will take the elevator 60 minutes to reach a depth of -350 meters.