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Differential Calculus> see attachment ...and please tell the met...

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see attachment ...and please tell the method which is used in solution please reply anyone ….i heard lot about this website

milind , 11 Years ago

Grade 12

1 Answers

Jitender Singh

Ans:

Hello student,
Please find the answer to your question below

$?L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+............+[\frac{3}{4}+\frac{99}{100}]$ $L = [\frac{3}{4}]+[\frac{3}{4}+\frac{1}{100}]+[\frac{3}{4}+\frac{2}{100}]+..........+[\frac{3}{4}+\frac{99}{100}]$
$[t] = 0, 0 <=t < 1$
$[t] = 1, 1 <= t < 2$
Now looking at the problem in hand
$[\frac{3}{4}+\frac{x}{100}] = 0, 0 <= x < 25$
$[\frac{3}{4}+\frac{x}{100}] = 0, 25 <= x < 99$
There are total 100 term in L out of which 25 terms are zero. Rest all the terms are equal to 1. So the sum is 75.

Last Activity: 11 Years ago

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