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Molar mass of CH2Cl2 = 12 × 1 + 1 × 2 + 35.5 × 2 = 85 g mol–1
Molar mass of CHCl3 = 12 × 1 + 1 × 1 + 35.5 × 3 = 119.5 g mol-1
Moles of CH2Cl2= 40 g /85 g mol = 0.47 mol
Moles of CHCl3 = 25.5 g /119.5 g mol = 0.213 mol
Total number of moles = 0.47 + 0.213 = 0.683 mol
Molefraction of component 2
= 0.47 mol / 0.683 mol = 0.688
Molefraction of component 1
= 1.00 – 0.688 = 0.312
We know that
Ptotal = (p2-p1)*x
= 200 + (415 – 200) × 0.688
= 200 + 147.9
= 347.9 mm Hg
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