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```
Vapour pressure of chloroform (CHCl3) and dichloromethane (CH2Cl2) at 25C are 200mm Hg and 41.5 mm Hg respectively. Vapour pressure of the solution obtained by mixing 25.5g of (CHCl2) and 40g of (CH2Cl2) at the same temperature will be (molecular mass of CHCl3 = 119.5 u and molecular mass of CH2Cl2 = 85 u )

```
3 years ago

Arun
24742 Points
```							Molar mass of CH2Cl2 = 12 × 1 + 1 × 2 + 35.5 × 2 = 85 g mol–1   Molar mass of CHCl3 = 12 × 1 + 1 × 1 + 35.5 × 3 = 119.5 g mol-1Moles of CH2Cl2= 40 g /85 g mol = 0.47 molMoles of CHCl3 = 25.5 g /119.5 g mol = 0.213 molTotal number of moles = 0.47 + 0.213 = 0.683 mol Molefraction of component 2 = 0.47 mol / 0.683 mol = 0.688Molefraction of component 1= 1.00 – 0.688 = 0.312 We know thatPtotal = (p2-p1)*x  = 200 + (415 – 200) × 0.688  = 200 + 147.9  = 347.9 mm Hg
```
3 years ago
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