Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

Two bodies are at temperature 27 degree centigrade and 927 degree centigrade. The heat energy radiated by them will be in the ratio: A. 1:4 B. 1: 64 C. 1:16 D. 1:256

Two bodies are at temperature 27 degree centigrade and 927 degree centigrade. The heat energy radiated by them will be in the ratio:
A. 1:4
B. 1: 64
C. 1:16
D. 1:256

Grade:12th pass

1 Answers

Arun
25763 Points
one year ago
According to Stephen's law of radiation energy , 
E  T⁴ 
Here E is the energy of radiation emitted and T is the temperature in Kelvin.
T₁ = 27°C = 27 + 273 = 300 K 
T₂ = 127°C = 927 + 273 = 1200 K 
Now, E₁/E₂ = T₁⁴/T₂⁴ 
E₁/E₂ = (1200/300)² = 256/1 
Hence, the ratio of energies of radiation emitted is 1: 256
 
 

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free