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The phase difference between two points separated by 0.8 m in a wave of frequency 120 Hz is o90. Then the velocity of wave will be

Deekshitha Kancharla , 5 Years ago
Grade 12
anser 1 Answers
swapna

 

Δϕ=90∘=2aa
Δx=0.8m
we know that Δϕ=α2π​×Δx
So λ=Δϕ2π×Δx​=π/22π×0.8​
⇒λ=3.2m
v=120Hz & v=vλ
velocityv=120×3.2=384m/s
Last Activity: 5 Years ago
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