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Grade 12Zoology

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Profile image of Shreya
8 Years agoGrade 12
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Profile image of Simran Vinaik
ApprovedApproved Tutor Answer8 Years ago
Frequency of R will be-( 120+20)/200= 0.7
Frequency of r will be -(20+40)/200= 0.3
So, frequency of heterozygote in next generation will be = 2pq--- 2*0.7*0.3
2pq= 0.42 or 42%