The image is attached within do help me to solve it out.....
Shreya
8 Years agoGrade 12
1 Answer
Simran Vinaik
Approved Tutor Answer8 Years ago
Frequency of R will be-( 120+20)/200= 0.7 Frequency of r will be -(20+40)/200= 0.3 So, frequency of heterozygote in next generation will be = 2pq--- 2*0.7*0.3 2pq= 0.42 or 42%