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Grade: 12th pass
        
 
The amount of heat required to convert 1 gm of ice at (minus)100 degree Celsius to steam at 100 degree Celsius is:
A. 766 cal 
B.  696 cal 
C. 716 cal 
D. 736 cal
one month ago

Answers : (1)

Vikas TU
8383 Points
							
Dear student 
I have given you the detailed solution , ask doubt what you did not understand, 
Please refer the solution, 

Mass of ice=1g

Temp of ice=0 degree C

1 First the ice at 0 degree C is to be converted into water at 0 degree C

Heat required at this stage

= Mass of the ice x Latent heat of fusion of ice

=1x 80 =80 cal

2 Now the temperature of water is to be increased from 0 to 100 degree C

Heat required for this =Mass of water x rise in temperature x specific heat of water

=1 x100 x1= 100 cal

3 Now this water at100 degree C is to be converted into vapour

Heat required for this

=Mass of water x Latent heat

= 1 x 536 =536 cal

Total heat required

  1. =80 +100 +536=716 cal
one month ago
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