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`         The amount of heat required to convert 1 gm of ice at (minus)100 degree Celsius to steam at 100 degree Celsius is:A. 766 cal B.  696 cal C. 716 cal D. 736 cal`
one month ago

Vikas TU
8383 Points
```							Dear student I have given you the detailed solution , ask doubt what you did not understand, Please refer the solution, Mass of ice=1gTemp of ice=0 degree C1 First the ice at 0 degree C is to be converted into water at 0 degree CHeat required at this stage= Mass of the ice x Latent heat of fusion of ice=1x 80 =80 cal2 Now the temperature of water is to be increased from 0 to 100 degree CHeat required for this =Mass of water x rise in temperature x specific heat of water=1 x100 x1= 100 cal3 Now this water at100 degree C is to be converted into vapourHeat required for this=Mass of water x Latent heat= 1 x 536 =536 calTotal heat required	=80 +100 +536=716 cal
```
one month ago
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