How much of sodium carbonate is required for complete neutralization of 18.25g of HCl?

A. 0. 25 mole

B. 0. 75 mole

C. 0. 50 mole

D. 1 mole

Dear student

2 moles of HCl is required with 1 mole of Na2 CO3

Moles of HCl present = 18.5/36.5 = 0.5 mole

So Na 2 CO3 required is 0.25 moles

Regards