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How much of sodium carbonate is required for complete neutralization of 18.25g of HCl? A. 0. 25 mole B. 0. 75 mole C. 0. 50 mole D. 1 mole

How much of sodium carbonate is required for complete neutralization of 18.25g of HCl? 
A. 0. 25 mole
B. 0. 75 mole
C. 0. 50 mole
D. 1 mole

Grade:12th pass

1 Answers

Saurabh Koranglekar
askIITians Faculty 10335 Points
4 years ago
Dear student

2 moles of HCl is required with 1 mole of Na2 CO3

Moles of HCl present = 18.5/36.5 = 0.5 mole

So Na 2 CO3 required is 0.25 moles

Regards

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