Arun
Last Activity: 7 Years ago
The frequency of the recessive allele is q = 0.4 (given)
Hence, p = 1-0.4 = 0.6 (as p = 1- q)
According to Hardy- Weinberg principle, p2 + ?2pq + q2 = 1.
hnce, p2 = (0.6)2 => 0.36
q2 = (0.4)2 => 0.16
2pq = 0.48
since, 2pq is the frequency of hetrozygous carrier,
= 0.48 X 200
=> 96 Individuals
