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Grade: 12

                        

A man whose father is a colourblind, marry a woman, who is a daughter of colourblind mother. The offspring of this couple will be (a) all daughter and sons are colourblind (b) 50% colourblind and 50% normal son (c) carrier normal daughter and colourblind sons (d) colourblind sons and normal daughter Please explain the solution in detail.

5 years ago

Answers : (1)

Komal
askIITians Faculty
747 Points
							carrier normal daughter and colourblind sons

Color blindless is an X-linked recessive disorder. Hence, the sex chromosomes (X and Y) are used when doing the punnet square.

-(c) can be used to represent color blindless, because it is the recessive trait.
-(C) can be used to represent the dominant allele for normal vision.

A man who is colorblind can be represented as (Xc Y)
A female with normal vision can be represented as (XC XC)

Hence, your cross is as follows:

(Xc Y) x (XC XC)

Based on this crossing, you can conclude that there is a 0% chance of producing a son who is colorblind. All males will have normal vision (XC Y)

From this crossing, you can also conclude that 100% of the females will be carriers (XC Xc), and thus have normal vision, because the allele for normal vision dominates the recessive allele for color blindness
5 years ago
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