When diffraction is performed in water then why will the fringes will be smaller in number than when it is performed in air?

Question

Arun · Answer

Maxima for a double slit occur when n lambda = d sin (thet a) so the angles between maxima (and hence the spacing) depends on sin(theta) Reaaranging: sin (theta) = n lambda/d When the apparatus is put in water, lambda changes. The velocity in water is less so mthe distance travelled durin on e period is less ie the wavelength (lambda) decreases. So sin(theta) decreases and hence the spacing between the maxima.

Thank you for registering.

Register Now and Win Upto 25% Scholorship for a Full Academic Year !

Enter Your Details

Registration done!

When diffraction is performed in water then why will the fringes will be smaller in number than when it is performed in air?

When diffraction is performed in water then why will the fringes will be smaller in number than when it is performed in air?

1 Answers

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

Other Related Questions on Wave Optics

ASK QUESTION

Answer and earn gift vouchers

View courses by askIITians

Design classes One-on-One in your own way with Top IITians/Medical Professionals

Complete Self Study Package designed by Industry Leading Experts

Live 1-1 coding classes to unleash the Creator in your Child

a Complete All-in-One Study package Fully Loaded inside a Tablet!

Register Now & Win Upto 25% Scholorship