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Two separate monochromatic light beams A and B of the same intensity are falling normally on a unit area of a metallic surface. Their wavelength are λA and λB respectively. Assuming that all the incident light is used in ejecting the photoelectrons, the ratio of the number of photoelectrons from the beam A to that from B is(1)(λA/λB)2(2)λA/λB(3)λB/λA(4)1

Nikhil , 7 Years ago
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anser 1 Answers
Mohit Bora

Last Activity: 7 Years ago

Answer is d .Because as both light beams A and B has capacity only to eject the electron not produce kinetic energy so the no. Of photoelectrons are equal in both and their ratio is 1.

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