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the wavelength of light used in two interference experiments are 500nm and 600nm if the fringe widths are equal when the screens are placed at 1m and 1.2m respectively the ratio of the distance between the slits is

the wavelength of light used in two interference experiments are 500nm and 600nm if the fringe widths are equal when the screens are placed at 1m and 1.2m respectively the ratio of the distance between the slits is

Grade:12

2 Answers

Bhumika biyani
35 Points
one year ago
Here the fringe width is equal so equate the formulas.
  lambda1 × D1 =  lambda2 × D2
           d1                       d2
          d2           =   600×1.2     =  36
          d1                 500×10          25
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