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Grade 12Wave Optics

The ratio of the width of the two slits in Youngs Double Slit experiment is 9:1 Prove that in the interference pattern
( Imax + Imin ) / ( Imax - Imin ) = 5/3.

Profile image of Vishakha Chourasia
11 Years agoGrade 12
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2 Answers

Profile image of Adarsh
11 Years ago
The two slits are coherent sources. The intensities of the light coming through these slits is directly proportional to the slit widths.
So,I1/I2 =9/1
Let I1=9I and I2=I
)]}2I1+2√(I2+I1)-[I2I1+2√(I2+I1)}/{I2I1+2√(I2+I1)+I2I1I√(+22+I1{I(Imax+Imin)/(Imax – Imin)=
=2(I1+I2)/4√(I1I2)=(2×10I)/(4×3I)
=10/(2×3)=5/3
Profile image of Adarsh
11 Years ago
I am again posting this answer because while uploading the above answer there was an error
The two slits are coherent sources. The intensities of the light coming through these slits is directly proportional to the slit widths.
So,I1/I2 =9/1
Let I1=9I and I2=I
(Imax+Imin)/(Imax – Imin)={I1+I2+2√(I1I2)+I1+I2-2√(I1I2)}/{I1+I2+2√(I2+I1)-[I1+I2-I√(I1I2)]}
=2(I1+I2)/4√(I1I2)=(2×10I)/(4×3I)
=10/(2×3)=5/3

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