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The maximum numbers of possible... (Please see the image for question)

The maximum numbers of possible... (Please see the image for question)

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Grade:12

1 Answers

Arun
25768 Points
3 years ago
Dear student
 
 – d sin @  = n* lambda
d = 2* lambda
2* lambda* sin @ = n * lambda
 
2 sin@ = n
 
interference maxima will be formed when n = 0, + 1, +2 ,  –1, –2
 
hence maximum number of possible interference = 5
 
 
Regards
Arun (askIITians forum expert)

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