Learn to Create a Robotic Device Using Arduino in the Free Webinar. Register Now
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Free webinar on Robotics (Block Chain) Learn to create a Robotic Device Using Arduino
30th Jan @ 5:00PM for Grade 1 to 10
The length of the wire shown in figure between the pulleys is 1.5 m and its mass is 12.0 g. Find the frequency of vibration with which the wire vibrates in two loops leaving the middle point of the wire between the pulleys at rest. The length of the wire shown in figure between the pulleys is 1.5 m and its mass is 12.0 g. Find thefrequency of vibration with which the wire vibrates in two loops leaving the middle point of the wire between the pulleys at rest.
Tension T= mg That is T= 9×9.8 = 88.2 N . mass per unit length of the string can be calculated, this is equal to 0.8 × 10^ -2 we know velocity of wave = √{tension/mass per unit length}So wave velocity is 105m/sIts given that there are 2 loops and the entire wire is vibrating except the mid point so it becomes a node. And 2loops , one up second down on either side of mid point , A wavelength. wavelength = length of wire 1.5 mWe know wavelength , velocity So frequency can be calculated by v=∆f where ∆ = wavelength Frequency is 70 Hz
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -