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The intensity at a point where the path difference is lambda/6 is I. If Io is the maximum intensity then I/Io is equal to?A) Root (3) / 2B) 1/2C) 3/4D) 1/Root (2)

Ashmeet Lamba , 8 Years ago
Grade 12th pass
anser 3 Answers
Vikas TU
The power at any given point in Experiment 
 
I = Io cos2(ѳ/2) 
 
I/I0 = Cos2(ѳ/2) 
 
Stage diff (Ѳ) =(2*Pi/lambda)*x 
 
=(2*Pi/lambda)*lambda/6 
 
Pi/3 
 
I/Io = (√3/2)2 
 
I/I0 = 3/4 
Last Activity: 8 Years ago
Harsh Jha
As we know that I=I1+I2+2(I1I2)^1/2cos(O).
where O is the phase difference. 
Also I1=I2. 
O=path difference*2(pi)/(lambda))=
Here path difference=lambda/6
Hence O=pi/3
 
I(nought)=Max Intensity(at cosO=1)=I1+I1+2(I1)*1=4I1
I=I1+I1+2(I1)cos(pi/3)=3I1
 
Hence I/I(nought)=3I1/4I1=3/4
Last Activity: 7 Years ago
Yash Chourasiya
Dear Student

Please see the solution in the attachment.
643-1742_a20.PNG

I hope this answer will help you.
Thanks & Regards
Yash Chourasiya
Last Activity: 5 Years ago
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