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Ratio of intensities between a point A and that of central fringe is 0.853. Then path difference between two waves at point A will be

 Ratio of intensities between a point A and that of central fringe is 0.853. Then path difference between two waves at point A will be 

Grade:8

1 Answers

Ashish Kumar
askIITians Faculty 32 Points
9 years ago
Intensity at a point = 4 I (cos A/2)^2 , where I is the intensity due a single slit and A is the phase difference between the light coming from the two slits.
given , 4 I (cos A/2)^2 / 4I =.853
cos A/2=.9235, A= 0.786 rad.
path difference = lambda* A /(2* pi) = 0.125 lambda (lambda =wavelength)



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