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n identical light waves each of intensity I are superposed in a homogeneous medium. The resultant intensity in their incoherent and coherent addition are respectively (1)zero and n^2 I(2)n I and n^2 I(3)n I and zero(4)n^2 I and n^2 I

Kanukolanu Meghana , 7 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar

Let's delve into the fascinating world of wave interference to address your question regarding the resultant intensity when identical light waves are superposed both incoherently and coherently. The behavior of these waves can vary significantly based on their phase relationship, which leads to different outcomes in terms of intensity.

Understanding Coherent and Incoherent Addition

When we talk about superposing light waves, we need to consider two types of addition: coherent and incoherent.

Coherent Addition

In coherent addition, the waves have a constant phase difference and their frequencies are identical. When n identical light waves, each with intensity I, interfere coherently, the resultant intensity can be calculated using the following formula:

  • Resultant Intensity (Iresultant) = n2 I

This means that if you have n waves, the intensity multiplies by n squared. For instance, if you have 3 waves each with an intensity of 1 unit, the total intensity would be:

  • Iresultant = 32 * 1 = 9 units

Incoherent Addition

On the other hand, incoherent addition occurs when the light waves are not in phase and do not have a consistent phase relationship. In this case, the waves simply add up their intensities without any interference effects.

  • Resultant Intensity (Iresultant) = n I

So if you have the same 3 waves, the total intensity would be:

  • Iresultant = 3 * 1 = 3 units

Choosing the Correct Option

With this understanding, let’s analyze the options you provided:

  • (1) zero and n2 I
  • (2) n I and n2 I
  • (3) n I and zero
  • (4) n2 I and n2 I

From our explanation, the coherent addition yields n2 I, and the incoherent addition gives us n I. Thus, the correct answer is:

(2) n I and n2 I

Final Thoughts

The distinction between coherent and incoherent addition of light waves is fundamental in understanding various optical phenomena, including interference and diffraction. This concept is widely applicable in fields such as telecommunications, optical engineering, and even in the study of quantum mechanics. Recognizing how these waves interact allows us to harness their properties for practical applications.

Last Activity: 5 Years ago
Vikas TU
Dear student 
If the potential difference between two waves is zero or is constant w.r.t time, then the two ways are said to be coherent.
The waves are non-coherent if the potential difference between the two ways keeps on changing. Lightbulb, study lamp are the examples of the coherent waves. They emit waves at random potential difference.
Now let us consider there are two needles say S1 and S2 moving up and down on the surface of the water and are pointing at point P. So the path difference here is given as  S1P –  S2P. Now the displacement by two needles and S1 S2 are:
y1 = A cos wt ……………… (1)
y2 = A cos wt …………….. (2)
So the resultant displacement at point P is, y =  y1  + y2. When we substitute the value of  y1  and y2  we write,
y = A cos wt + A cos wt
y = 2A cos wt……………….. (3)
Now, we know the intensity is proportional to the square of the amplitude waves.
I0  ∝ A²
Where I0  is the initial intensity and  A² is the amplitude of the wave. From equation 3, we say that A = 2A. So,
I0  ∝ (2A)² or I0  ∝ 4 A²
I = 4 I0    
Now, if two needles that are S1 are S2 are in the same phase, the potential difference is,
S1P  – S2P = nλ
Where n = 0, 1, 2,3 ……… and λ = the wavelength of the wave. If the two needles  S1 and S2 are vibrating at its destructive interference then, the potential difference is
S1P –  S2P = (n + 1/2) λ
Now if the potential difference of the waves is Φ then,
y1  = α cos wt
 y2 = α cos wt
The individual intensity of each wave is  I0 , we get,
y =  y1  + y2
= α cos wt + α cos (wt +Φ)
y = 2 α cos(Φ/2) cos (wt + Φ/2)
Since, the intensity is I0 ∝ A²
I0 ∝ 4α² cos² (Φ/2)
I = 4 I0  cos² (Φ/2)
Well, the time-averaged value of cos²(Φt/2) is 1/2. So, the resultant intensity will be  I = 2 I0 at all the points.
Last Activity: 5 Years ago
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