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Maximum intensity in Young's double slit experiment is I. Then what is the intensity at a point on the screen where the path difference between them is lambda/4?

Yoshita Kalla , 10 Years ago
Grade 12th pass
anser 1 Answers
Saurabh Kumar
Phase difference = k x path difference
Then calculating Intensity, as is is a function of phase difference.
Last Activity: 10 Years ago
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