interference fringes are observed by a byprism of refracting angle 1degree and refractive index 1.5 on a screen placed 100cm away . the wavelength of light used is 5890 angstrom . distance of source from prism is 20 cm . what is the fringe width

Question

Deep Jyoti Rabha · Answer

given, n=1.5 r=20cm D=100+20 A=1 0 =120cm =0.0174 radian = (1.5-1)*0.0174 =0.0087266 = 2*20*0.0087266 = 0.349 cm = (120*5890*10 -8 )/0.349 = 0.02024 cm = 0.202 mm

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interference fringes are observed by a byprism of refracting angle 1degree and refractive index 1.5 on a screen placed 100cm away . the wavelength of light used is 5890 angstrom . distance of source from prism is 20 cm . what is the fringe width

interference fringes are observed by a byprism of refracting angle 1degree and refractive index 1.5 on a screen placed 100cm away . the wavelength of light used is 5890 angstrom . distance of source from prism is 20 cm . what is the fringe width

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