In youngs double slit experiment with wavelength 5890A°; there are 60 fringes in the field of vision. How many fringes will be observed in the same field of vision if wavelength used is5460A°

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Vikas TU · Answer

Number of edges is straightforwardly relative to the wavelength N1 α ƛ1 N2 α ƛ2 N1/N2 = ƛ1/ƛ2  60/N2 = 5890/5460  N2 = (5460 *60)/5890  N2 = 55

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In youngs double slit experiment with wavelength 5890A°; there are 60 fringes in the field of vision. How many fringes will be observed in the same field of vision if wavelength used is5460A°

In youngs double slit experiment with wavelength 5890A°; there are 60 fringes in the field of vision. How many fringes will be observed in the same field of vision if wavelength used is5460A°

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