In the YDSE the slits are 0.5mm apart and intefer

Question

In the YDSE the slits are 0.5mm apart and inteference is observed on a screen placed at a distance of 100cm from the slits . it is found that the 9th bright fringe is at a distane of 9mm from the second dark fringe from the centre of the fringe pattern. what is the wavelnght of light used ?

Arun · Accepted Answer

d = 0.5 mm= 0.5 × 10–3 m= 5 × 10–4 mD = 100 cm = 1 m X9 – X′2= 8.835 mm[Assuming both bright and dark fringesare on same side of centre of fringepattern]= 8.835 × 10–3 mTo Find :λ = ?Formula :λ =Xd/DSince distance of nth bright bandXn = nλD/dX9 = 9λD/dX2' = (2*2- 1) λD/2dX2' = 3λD/2dX9 - X2' = 15λD/2dNow you can find λWhere X9-X2' = 9 mmHope it helps

Wave Optics> In the YDSE the slits are 0.5mm apart and...

In the YDSE the slits are 0.5mm apart and inteference is observed on a screen placed at a distance of 100cm from the slits . it is found that the 9^th bright fringe is at a distane of 9mm from the second dark fringe from the centre of the fringe pattern. what is the wavelnght of light used ?

Ashwin , 7 Years ago

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Wave Optics> In the YDSE the slits are 0.5mm apart and...

In the YDSE the slits are 0.5mm apart and inteference is observed on a screen placed at a distance of 100cm from the slits . it is found that the 9th bright fringe is at a distane of 9mm from the second dark fringe from the centre of the fringe pattern. what is the wavelnght of light used ?

Ashwin , 7 Years ago

Arun

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