in the arrangement shown in figure, image of a light sorce o is obtained at the bottom of a beaker containing water of refractive index 4/3. the value of H is

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Vikas TU · Answer

Dear student Please refer the below link for similar question https://www.askiitians.com/forums/General-Physics/9/46084/phyics.htm Good Luck Cheers

Arun · Answer

As seen from out side shift observed due to water is t×(1−μ1)=10×(1−43)=2.5

and for the mirror object distance is 5+10−2.5=12.5

Hence the image distance from mirror is 12.5,

Rishi Sharma · Answer

Dear Student,
Please find below the solution to your problem.

As seen from out side shift observed due to water is t×(1-1/μ)=10×(1−3/4)=2.5
and for the mirror object distance is 5+10−2.5=12.5
Hence the image distance from mirror is 12.5,
Hence option B is correct .

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in the arrangement shown in figure, image of a light sorce o is obtained at the bottom of a beaker containing water of refractive index 4/3. the value of H is

in the arrangement shown in figure, image of a light sorce o is obtained at the bottom of a beaker containing water of refractive index 4/3. the value of H is

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