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in the arrangement shown in figure, image of a light sorce o is obtained at the bottom of a beaker containing water of refractive index 4/3. the value of H is
Dear student Please refer the below link for similar question https://www.askiitians.com/forums/General-Physics/9/46084/phyics.htmGood Luck Cheers
As seen from out side shift observed due to water is t×(1−μ1)=10×(1−43)=2.5and for the mirror object distance is 5+10−2.5=12.5Hence the image distance from mirror is 12.5,
Dear Student,Please find below the solution to your problem.As seen from out side shift observed due to water is t×(1-1/μ)=10×(1−3/4)=2.5and for the mirror object distance is 5+10−2.5=12.5Hence the image distance from mirror is 12.5,Hence option B is correct .Thanks and Regards
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