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Grade 12th passWave Motion

in compound microscope fo and fe are 5cm and 10 cm an image is formed by the objective at distance of 15cm very close to eye piece its magnification is.a. 6b.7c.8d.9

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8 Years agoGrade 12th pass
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ApprovedApproved Tutor Answer1 Year ago

To determine the magnification of a compound microscope given the focal lengths of the objective and eyepiece, as well as the distance at which the image is formed, we can use the formula for magnification in a compound microscope. The magnification (M) is the product of the magnification of the objective (Mo) and the magnification of the eyepiece (Me).

Understanding the Components

In this scenario, we have:

  • Focal length of the objective (fo): 5 cm
  • Focal length of the eyepiece (fe): 10 cm
  • Image distance from the objective (v): 15 cm

Calculating the Objective Magnification

The magnification of the objective (Mo) can be calculated using the formula:

Mo = v / (v - fo)

Substituting the values:

Mo = 15 cm / (15 cm - 5 cm) = 15 cm / 10 cm = 1.5

Calculating the Eyepiece Magnification

The eyepiece magnification (Me) is calculated using the formula:

Me = D / fe

Where D is the near point distance, typically taken as 25 cm for a relaxed eye. Thus:

Me = 25 cm / 10 cm = 2.5

Finding Total Magnification

The total magnification (M) of the compound microscope is the product of the objective and eyepiece magnifications:

M = Mo × Me

Substituting the values we calculated:

M = 1.5 × 2.5 = 3.75

Revisiting the Problem

It seems there might be a misunderstanding regarding the values or the setup, as the calculated magnification does not match any of the options provided (6, 7, 8, or 9). It's essential to ensure that the distances and focal lengths are correctly interpreted and applied. If the image distance or any other parameters were different, it could lead to a different magnification result.

Final Thoughts

In practical terms, if you were to adjust the parameters or clarify any additional details about the setup, we could re-evaluate the magnification. Understanding how each component of the microscope contributes to the overall magnification is crucial for effective use and analysis.