Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
```        In an experiment with Foucault’s apparatus, the various distance used are as follows:
Distance between the rotating and the fixed mirror = 16
Distance between the lens and the rotating mirror = 6 m,
Distance between the source and the lens = 2 m.
When the mirror is rotated at a speed of 356 revolutions per second, the image shifts by 0.7 mm. Calculate the speed of light from these data.
```
5 years ago

```							Sol. In the given Focault experiment,
R = Distance between fixed and rotating mirror = 16m
ω = Angular speed = 356 rev/’ = 356 × 2π rad/sec
b = Distance between lens and rotating mirror = 6m
a = Distance between source and lens = 2m
s = shift in image = 0.7 cm = 0.7 × 10^–3 m
So, speed of light is given by,
C = 4R^2ωa/s(R + b) = 4 * 16^2 * 356 * 2π * 2/0.7 * 10^-3(16 + 6) = 2.975 * 10^8 m/s

```
5 years ago
Think You Can Provide A Better Answer ?

## Other Related Questions on Wave Optics

View all Questions »  ### Course Features

• 101 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution  ### Course Features

• 110 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions