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In a Michelson experiment for measuring speed of light, the distance travelled by light between two reflections from the rotating mirror is 4.8 km. The rotating mirror has a shape of a regular octagon. At what minimum angular speed of the mirror (other than zero) the image is formed at the position where a nonrotating mirror forms it?

In a Michelson experiment for measuring speed of light, the distance travelled by light between two reflections from the rotating mirror is 4.8 km. The rotating mirror has a shape of a regular octagon. At what minimum angular speed of the mirror (other than zero) the image is formed at the position where a nonrotating mirror forms it?

Grade:upto college level

1 Answers

Jitender Pal
askIITians Faculty 365 Points
6 years ago
Sol. In the given Michelson experiment, D = 4.8 km = 4.8 × 10^3 m N = 8 We know, c = DωN/2π ⇒ ω = 2πc/DN rad/sec = c/DN rev/sec = 3 * 10^8/4.8 * 10^3 * 8 = 7.8 * 10^3 rev/sec

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