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If the wavelength of the light falling on a surface is increased from 3000 Å to 3040 Å, then what will be the corresponding change in the stopping potential? (Given that hc = 12.4  103 eV Å)

karthik , 8 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar
Dear student

Please write the Question in a standard form or attach an image of the question

Regards
Last Activity: 5 Years ago
Arun
Dear student
 

ΔV=eΔEincident 

(λ1hcλ2hc)

=4.1334.078

=5.5×102V

 

Hope it helps

In case of any difficulty, Please feel free to ask again

Last Activity: 5 Years ago
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