Guest

If the wavelength of the light falling on a surface is increased from 3000 Å to 3040 Å, then what will be the corresponding change in the stopping potential? (Given that hc = 12.4  103 eV Å)

If the wavelength of the light falling on a surface is increased from 3000 Å to 3040 Å, then what will be the corresponding change in the stopping potential? (Given that hc = 12.4  103 eV Å)

Grade:12

2 Answers

Saurabh Koranglekar
askIITians Faculty 10336 Points
2 years ago
Dear student

Please write the Question in a standard form or attach an image of the question

Regards
Arun
25758 Points
2 years ago
Dear student
 

ΔV=eΔEincident 

(λ1hcλ2hc)

=4.1334.078

=5.5×102V

 

Hope it helps

In case of any difficulty, Please feel free to ask again

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free