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If the wavelength of the light falling on a surface is increased from 3000 Å to 3040 Å, then what will be the corresponding change in the stopping potential? (Given that hc = 12.4  103 eV Å)

karthik , 7 Years ago
Grade 12
anser 2 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

Please write the Question in a standard form or attach an image of the question

Regards

Arun

Last Activity: 5 Years ago

Dear student
 

ΔV=eΔEincident​​ 

(λ1​hc​−λ2​hc​)

=4.133−4.078

=5.5×10−2V

 

Hope it helps

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