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If the intensity is increased by a factor of 20, by how many decibels is the sound level increased?

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3 years ago

```							If the intensity of sound in watts per square metre is I, then the intensity level in decibel (dB) is given bydB= 10 log(I/I•),Where the base of logarithm is 10,I•=10^-12 watt per square metre( roughly the intensity at which audible sound can be heard)On the decibel scale the pain threshold is 1 watt per square metre and on decibel scale is:dB= 10 log(1 watt per square metre/10^-12 watt per square metre)dB= 10 log ( 1/10^-12)= 10* log (10^12)=10*12=120 dBIn the given problemdB= 10 log ( 20 I/I)= 10* log 20=10*1.3010=13dB
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3 years ago
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