if the angle between the pass axis of polariser and analyser is 45 degree write the ratio of intensitiesof orginal light and the transmitted light after passing through the analyser

Let the intensity of the original light is I₀.

In acoordance to Malu’s law, the intensity of transmitted light after passing through the analyser will be,

I (θ) = I₀cos²θ
Hereθ =45°
So,I (θ) = I₀cos²(45°) = I₀/2
Thus, I₀/I = 2
From the above observation we conclude that,the ratio of intensities of orginal light and the transmitted light after passing through the analyser will be 2.

Dear Student,
Please find below the solution to your problem.

Let the intensity of the original light is I0.
In acoordance to Malu’s law, the intensity of transmitted light after passing through the analyser will be,
I (θ) = I0cos2θ
Hereθ = 45°
So,I (θ) = I0cos2(45°)
= I0/2
Thus, I0/I = 2
From
the above observation we conclude that,the ratio of intensities of
orginal light and the transmitted light after passing through the
analyser will be 2.

Thanks and Regards