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If one of two identical slots producing interference in young`s experiment is covered with glass so that the light intensity passing through it is reduced to 50% find the ratio of the maximum and minimum intensity of the fridge in the interference pattern.

Sparsh , 7 Years ago

Grade 12

2 Answers

Khimraj

I₁/I₂ = 2

I_max/I_min = [( $\sqrt{I_{1}^{}}$ + $\sqrt{I_{2}^{}}$ )/( $\sqrt{I_{1}^{}}$ – $\sqrt{I_{2}^{}}$ )]² = [( $\sqrt{I_{2}/I_{1}}$ +1)/( $\sqrt{I_{2}/I_{1}}$ – 1 )]²

= [(2+1)/(2-1)]² = 9.

Hope it clears.If you like answer then please approve it.

Last Activity: 7 Years ago

Romy

I1/I2 = 2Imax/Imin = [(\sqrt{I_{1}^{}} +\sqrt{I_{2}^{}})/(\sqrt{I_{1}^{}} – \sqrt{I_{2}^{}})]2 = [(\sqrt{I_{2}/I_{1}} +1)/(\sqrt{I_{2}/I_{1}} – 1 )]2 = [(√2+1)/(√2-1)]2 = (3+2√2)/(3-2√2).

Last Activity: 7 Years ago

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