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# i need answer for the question which is in image format please check the attached image.

Shoubhik
26 Points
4 years ago
For angle of refraction, we have:
$Sin \theta =\frac{\mu _{2}}{\mu _{1}}$
Where: $\mu _{2}$ is refractive index of water.
$\mu _{1}$ is refractive index of air.
Solving, we get
$\theta = Sin^{-1}\frac{\mu _{2}}{\mu_{1}}$
$\theta =37^{o}$