For the given incident ray ( refer to the image attached) the condition for total internal reflection of this ray the required refractive index of prism will be

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the first equation is sin45×1=sin∂×Refractive index (snells law) 2.the second eq.is sin(90-∂)×refractive index=sin90×1 solve for refractive index

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For the given incident ray ( refer to the image attached) the condition for total internal reflection of this ray the required refractive index of prism will be

For the given incident ray ( refer to the image attached) the condition for total internal reflection of this ray the required refractive index of prism will be

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For the given incident ray ( refer to the image attached) the condition for total internal reflection of this ray the required refractive index of prism will be

For the given incident ray ( refer to the image attached) the condition for total internal reflection of this ray the required refractive index of prism will be

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