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For a prism of refracting angle 45° , u=1.5 for a light of certain wavelength.What should be the maximum angle of
incidence for the ray so that no total internal reflection takes place for the emergent ray?

Mohammed Aman , 9 Years ago
Grade 11
anser 1 Answers
Askiitians Tutor Team

To determine the maximum angle of incidence for a ray of light passing through a prism with a refracting angle of 45° and a refractive index of 1.5, we need to consider the conditions for refraction and total internal reflection. Let's break this down step by step.

Understanding Refraction and Total Internal Reflection

When light travels from one medium to another, it bends at the interface due to a change in speed. This bending is described by Snell's Law, which states:

n1 * sin(θ1) = n2 * sin(θ2)

Where:

  • n1 is the refractive index of the first medium (air, in this case, which is approximately 1).
  • θ1 is the angle of incidence.
  • n2 is the refractive index of the second medium (the prism, which is 1.5).
  • θ2 is the angle of refraction.

Conditions for No Total Internal Reflection

Total internal reflection occurs when light attempts to move from a denser medium to a less dense medium at an angle greater than the critical angle. The critical angle can be calculated using the formula:

sin(θc) = n2 / n1

For our scenario:

  • n2 = 1.5 (the prism)
  • n1 = 1 (air)

Thus, the critical angle (θc) can be calculated as follows:

sin(θc) = 1 / 1.5

θc = sin⁻¹(1 / 1.5) ≈ 41.81°

Finding the Maximum Angle of Incidence

To ensure that no total internal reflection occurs, the angle of refraction (θ2) must be less than the critical angle (θc). Since the prism has a refracting angle of 45°, we can apply the prism formula:

θ1 + θ2 = A

Where A is the refracting angle of the prism (45°). Rearranging gives:

θ2 = A - θ1

Substituting the critical angle into this equation, we have:

θ2 < θc

A - θ1 < θc

Substituting the known values:

45° - θ1 < 41.81°

Rearranging this inequality gives:

θ1 > 45° - 41.81°

θ1 > 3.19°

Conclusion on Maximum Angle of Incidence

Therefore, the maximum angle of incidence (θ1) for the ray of light to ensure that no total internal reflection occurs in the prism is approximately:

θ1 = 3.19°

This means that if the angle of incidence is greater than 3.19°, total internal reflection could occur, preventing the light from emerging from the prism. Thus, keeping the angle of incidence below this threshold will allow the light to pass through the prism without any issues.

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