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Find the maximum kinetic energy of the photoelectrons ejected when light of wavelength 350 nm is
incident on a cesium surface. Work function of cesium = 1.9 eV.

karthik , 8 Years ago
Grade 12
anser 1 Answers
Arun
 λ = 350 nn = 350 * 10^-9 m ∅ = 1.9 eV Max KE of electrons =- =hC/λ - ∅ = 6.63 * 10^-34 *3 * 10^8/350 * 10^-9 * 1.6 * 10^-19= 1.65 ev = 1.6 ev. 
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Last Activity: 8 Years ago
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