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(f_0/f_e )=10.
From the given magnification, we find that f0 = 10 fe.
Therefore, 10 fe + fe = 44 or 11 fe = 44 or fe= 4.
And focal length of the objective (f0) = 44 - fe = 44 - 4 = 40 cm.
Regards
Arun (askIITians forum expert)
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