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An astronomical telescope of ten fold angular magnification has a length of the 44 cm. The focal length of the objective is. A. 4cmB.40cmC.44cmD . 440 cm

Shuchi , 6 Years ago
Grade 12th pass
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear Shuchi
 
Given: Length of astronomical telescope (f0+ fe) = 44 cm and magnification

(f_0/f_e )=10.

From the given magnification, we find that f0 = 10 fe.

Therefore, 10 fe + fe = 44 or 11 fe = 44 or fe= 4.

And focal length of the objective (f0) = 44 - fe = 44 - 4 = 40 cm.

 

Regards

Arun (askIITians forum expert)

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