After solving.. n came out to be 13.85.. and final ans is 14... I think it should be 13.. since it's about number of reflections so what I think it's that we cannot take approximations and approximate 13.85 to 14 ... Pls explain where am I thinking wrong..

Question

Arun · Answer

here, BC = 20cm ABC = CBD = 30o Now, in triangle BCD DC = BCtan30 = 20.tan30 thus, DC = 20/√3cm thus, the ray of light undergoes one reflection for every horizontal distance of 20/√3cm. The total distance covered to make all the reflections will be now, the number of reflections will be [length of mirror = 1.6m = 160cm] = 160 / (20/√3) ~ 14 reflections

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After solving.. n came out to be 13.85.. and final ans is 14... I think it should be 13.. since it's about number of reflections so what I think it's that we cannot take approximations and approximate 13.85 to 14 ... Pls explain where am I thinking wrong..

After solving.. n came out to be 13.85.. and final ans is 14... I think it should be 13.. since it's about number of reflections so what I think it's that we cannot take approximations and approximate 13.85 to 14 ... Pls explain where am I thinking wrong..

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