A transverse wave described by y = (0.02 m) sin [(1.0 m–1)x + (30 s–1)] propagates on a stretched string having a linear mass density of 1.2 x 10–4 kg/m. Find the tension in the string.

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S sai Suhrut · Answer

let T= tension linear masss density (m) =1.2x 10^-4 kg/m we know wave speed = w/k= 30/1=30m/s imples that we know v=√(T/m) implies that 30= √(T/m) => 900* 1.2 x 10^-4=T => T=0.108 N

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A transverse wave described by y = (0.02 m) sin [(1.0 m–1)x + (30 s–1)] propagates on a stretched string having a linear mass density of 1.2 x 10–4 kg/m. Find the tension in the string.

A transverse wave described by y = (0.02 m) sin [(1.0 m–1)x + (30 s–1)] propagates on a stretched string having a linear mass density of 1.2 x 10–4 kg/m. Find the tension in the string.

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A transverse wave described by y = (0.02 m) sin [(1.0 m–1)x + (30 s–1)] propagates on a stretched string having a linear mass density of 1.2 x 10–4 kg/m. Find the tension in the string.

A transverse wave described by y = (0.02 m) sin [(1.0 m–1)x + (30 s–1)] propagates on a stretched string having a linear mass density of 1.2 x 10–4 kg/m. Find the tension in the string.

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