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Grade: 12th pass

                        

A thin film of thickness t and index of refraction 1.33 coats a glass with index of refraction 1.50.What is the least thickness t that will strongly reflect light with wavelength 600nm incident normally

7 months ago

Answers : (3)

Arun
25768 Points
							
Expression of Least thickness t that will strongly reflect  light:
 
since, t = nλ/2μ
 
Here,
 
λ = Wavelength = 600 nm
 
μ = Refractive index of film = 1.33
 
For least thickness : n = 1
 
Hence,
 
t = λ / 2μ
 
= 600 / 2*1.33
 
= 600/ 2.66
 
= 225.56
 
≈ 225 nm
 
Thus, least thickness t that will strongly reflect  light with wavelength 600nm incident normally is 225 nm.
 
Thanks and regards
7 months ago
suresh kumar
37 Points
							

the condition is 2μtcosr = nλ

for normal incident r = 90

hence 2μt = nλ

so,  t = nλ/2μ

Here,

λ = Wavelength = 600 nm

μ = Refractive index of film = 1.33

For least thickness : n = 1

Hence,

t = λ / 2μ

= 600 / 2*1.33

= 600/ 2.66

= 225.56

≈ 225 nm

none of the options are correct. But we can take nearest answer whic is 200nm

7 months ago
suresh kumar
37 Points
							

the condition is 2μtcosr = nλ

for normal incident r = 0 deg

hence 2μt = nλ

so,  t = nλ/2μ

Here,

λ = Wavelength = 600 nm

μ = Refractive index of film = 1.33

For least thickness : n = 1

Hence,

t = λ / 2μ

= 600 / 2*1.33

= 600/ 2.66

= 225.56

≈ 225 nm

none of the options are correct. But we can take nearest answer whic is 200nm

7 months ago
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