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the condition is 2μtcosr = nλ
for normal incident r = 90
hence 2μt = nλ
so, t = nλ/2μ
Here,
λ = Wavelength = 600 nm
μ = Refractive index of film = 1.33
For least thickness : n = 1
Hence,
t = λ / 2μ
= 600 / 2*1.33
= 600/ 2.66
= 225.56
≈ 225 nm
none of the options are correct. But we can take nearest answer whic is 200nm
for normal incident r = 0 deg
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