A thin film of thickness t and index of refraction 1.33 coats a glass with index of refraction 1.50.What is the least thickness t that will strongly reflect light with wavelength 600nm incident normally

Question

Arun · Answer

Expression of Least thickness t that will strongly reflect light: since, t = nλ/2μ Here, λ = Wavelength = 600 nm μ = Refractive index of film = 1.33 For least thickness : n = 1 Hence, t = λ / 2μ = 600 / 2*1.33 = 600/ 2.66 = 225.56 ≈ 225 nm Thus, least thickness t that will strongly reflect light with wavelength 600nm incident normally is 225 nm. Thanks and regards

suresh kumar · Answer

the condition is 2 μtcosr = nλ for normal incident r = 90 hence 2 μt = nλ so, t = nλ/2μ Here, λ = Wavelength = 600 nm μ = Refractive index of film = 1.33 For least thickness : n = 1 Hence, t = λ / 2μ = 600 / 2*1.33 = 600/ 2.66 = 225.56 ≈ 225 nm none of the options are correct. But we can take nearest answer whic is 200nm

suresh kumar · Answer

the condition is 2 μtcosr = nλ for normal incident r = 0 deg hence 2 μt = nλ so, t = nλ/2μ Here, λ = Wavelength = 600 nm μ = Refractive index of film = 1.33 For least thickness : n = 1 Hence, t = λ / 2μ = 600 / 2*1.33 = 600/ 2.66 = 225.56 ≈ 225 nm none of the options are correct. But we can take nearest answer whic is 200nm

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A thin film of thickness t and index of refraction 1.33 coats a glass with index of refraction 1.50.What is the least thickness t that will strongly reflect light with wavelength 600nm incident normally

A thin film of thickness t and index of refraction 1.33 coats a glass with index of refraction 1.50.What is the least thickness t that will strongly reflect light with wavelength 600nm incident normally

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