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A thin equilateral prism has refractive index of 1.5.find the angle of minimum deviation. Sir how to solve it?
Refractive index = 1.5Hence1.5 = [sin(A + )/2 ]/sin A/2A = 60°Now1.5 sin60/2 = sin(60+)/21.5 * 1/2 = sin(60 + )/248.6 ° = (60 + )/297.2 -60 = = 37.2° RegardsArun (askIITians forum expert)
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