A thin equilateral prism has refractive index of 1.5.find the angle of minimum deviation. Sir how to solve it?

Question

Arun · Answer

Refractive index = 1.5 Hence 1.5 = [sin(A + )/2 ]/sin A/2 A = 60° Now 1.5 sin60/2 = sin(60+ )/2 1.5 * 1/2 = sin(60 + )/2 48.6 ° = (60 + )/2 97.2 -60 = = 37.2° Regards Arun (askIITians forum expert)

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A thin equilateral prism has refractive index of 1.5.find the angle of minimum deviation. Sir how to solve it?

A thin equilateral prism has refractive index of 1.5.find the angle of minimum deviation. Sir how to solve it?

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