Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
A string of length 40 cm and weighing 10 g is attached to a spring at one end and to a fixed wall at the other end. The spring has a spring constant of 160 N/m and is stretched by 1.0 cm. If a wave pulse is produced on the string near the wall, how much time will it take to reach the spring?
l = 40 cm, mass = 10 g ∴ mass per unit length, m = 10 / 40 = 1/4 (g/cm) spring constant K = 160 N/m deflection = x = 1 cm = 0.01 m ⇒ T = kx = 160 * 0.01 = 1.6 N = 16 * 104 dyne Again v = √(T /m) = √(16 *104 /(1/ 4) = 8 * 102 cm/s = 800 cm/s ∴ Time taken by the pulse to reach the spring t = 40/800 = 1/20 = 0/05 sec.
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -