# A ray of light is incident at an angle of 60 degree on one face of a prism of angle 30 degree.The angle deviation is 30 degree.The emergent ray is inclined with the face at which it emeges at an angle a)90 b)0 c)30 d)60 given ans is 90 degree how?

Arun
25750 Points
6 years ago

All the angles should be in degree

For  a prism of angle of refraction A , the angle of deviation for an angle of incidence i is given by, δ=i+e−A

The angle of incidence i = 60°. Angle of prism A = 30°. Angle between incident and emergent ray is called angle of deviation, δ = 30°.

Using Snells law

In the triangle , Angle at which it emerges is 90°.

Rishi Sharma
4 years ago
Dear Student,

For a prism of angle of refraction A , the angle of deviation for an angle of incidence i is given by, δ=i+e−A
In the given condition
the angle of incidence i = 60°
angle of prism A = 30°
angle between incident and emergent ray is called angle of deviation, δ = 30°.
Using Snells law
In the triangle , Angle at which it emerges is 90°
NOTE: All the angles should be in degree.

Thanks and Regards.