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A ray of light falling at an angle of 50o is refracted through a prism in minimum deviation position. Theangle of the prism is 60o. Calculate the refractive index of the prism. Given that sin 50o = 0.766

sandeep , 7 Years ago
Grade 12
anser 1 Answers
Vikas TU

Last Activity: 7 Years ago

Dear Student,
i1=50⁰ (Angle of rate) 
we realize that for least deviation condition, 
2i1=A+min (A=Angle of crystal, min= Minimum deviation point) 
=>2x50=60+min 
=>min=40⁰ 
µ=refractive index= sin((A+min)/2)/sin(A/2) 
=>µ=sin50/sin30 
=>µ=1.532 
Cheers!!
Regards,
Vikas (B. Tech. 4th year
Thapar University)

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