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A Polarised and an analyser are oriented so that the maximum light is transmitted. what is the fraction of maximum light transmitted when analyser is rotated through (1) 30 degree(2) 60 degree

Harshita jaiswal , 6 Years ago
Grade 12
anser 1 Answers
Arun

Last Activity: 6 Years ago

Dear Harshita
since
I=I0/2(when light pas through polaraiser)
and
I'=I cos2theta
so
(i)
finally we have
I'=(I/2)cos²30°   
=(I/2)(3/4)
=(3/8)
ii)
I = (I/2) cos² 60°
= (I/2) (1/4)
= 1/8
Regards
Arun

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