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A Polarised and an analyser are oriented so that the maximum light is transmitted. what is the fraction of maximum light transmitted when analyser is rotated through (1) 30 degree (2) 60 degree

A Polarised and an analyser are oriented so that the maximum light is transmitted. what is the fraction of maximum light transmitted when analyser is rotated through (1) 30 degree (2) 60 degree

Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear Harshita
since
I=I0/2(when light pas through polaraiser)
and
I'=I cos2theta
so
(i)
finally we have
I'=(I/2)cos²30°   
=(I/2)(3/4)
=(3/8)
ii)
I = (I/2) cos² 60°
= (I/2) (1/4)
= 1/8
Regards
Arun

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