A Polarised and an analyser are oriented so that the maximum light is transmitted. what is the fraction of maximum light transmitted when analyser is rotated through (1) 30 degree(2) 60 degree ?
Harshita jaiswal , 6 Years ago
Grade 12
1 Answers
Arun
Last Activity: 6 Years ago
Dear Harshita since I=I0/2(when light pas through polaraiser) and I'=I cos2theta so (i) finally we have I'=(I/2)cos²30° =(I/2)(3/4) =(3/8) ii) I'= (I/2) cos² 60° = (I/2) (1/4) = 1/8 Regards Arun (askIITians forum expert)
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