A polarised & an analyser are oriented so that the maximum light is transmitted. What is the fraction of maximum light transmitted when analyser is rotated through (1) 30 degree (2) 60 degree ?
Harshita jaiswal , 7 Years ago
Grade 12
1 Answers
Arun
Last Activity: 7 Years ago
Dear Harshita since I=I0/2(when light pas through polaraiser) and I'=I cos2theta so (i) finally we have I'=(I/2)cos²30° =(I/2)(3/4) =(3/8) ii) I = (I/2) cos² 60° = (I/2) (1/4) = 1/8 Regards Arun
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