A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at their
mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

Question

Arun · Answer

Tr

Arun · Answer

Time period, T = 4 * 5 ms = 20 * 10–3 = 2 * 10–2 s λ = 2 * 2 cm = 4 cm frequency, f = 1/T = 1/(2 * 10–2) = 50 s–1 = 50 Hz Wave speed = λ f = 4 * 50 m/s = 2000 m/s = 2 m/s

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A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at their
mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

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A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at theirmean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.

2 Answers

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A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from Its mean position to the extreme position. The distance between two consecutive particles, which are at their
mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.