Jitender Pal
Last Activity: 10 Years ago
Sol. The lady uses +1.5D glasses to have normal vision at 25 cm.
So, with the glasses, her least distance of clear vision = D = 25 cm
Focal length of the glasses = 1/1.5 m = 100/1.5 cm
So, without the glasses her least distance of distinct vision should be more
If, u = - 25cm, f = 100/1.5 cm
Now, 1/v – 1/u = 1/f = 1.5/100 – 1/25 = 1.5 – 4/100 = -235/100 ⇒ v = - 40cm = near point without glasses.
Focal length of magnifying glass = 1/20 m = 0.05m = 5 cm = f
(a) The maximum magnifying power with glasses
m = 1 + D/f = 1 + 25/5 = 6 [∵ D = 25cm]
(b) without the glasses, D = 40cm
So, m = 1 + D/f = 1 + 40/5 = 9