A fish looking up through the tank sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface,what is the radius of the circle in cm ? (please see attachment for diagram)

Question

Arun · Answer

After makig the figure U would get the final relation as tanthetha = r/h where thetha is the angle making with height h (perpendicular and the hypertenuse.) and this angle is also the TIR angle. Therfore from, sinthetha = 1/u = ¾ thanthetha = 3/root(7) and r = 36/root(7)

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A fish looking up through the tank sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface,what is the radius of the circle in cm ? (please see attachment for diagram)

A fish looking up through the tank sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface,what is the radius of the circle in cm ? (please see attachment for diagram)

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A fish looking up through the tank sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface,what is the radius of the circle in cm ? (please see attachment for diagram)

A fish looking up through the tank sees the outside world contained in a circular horizon. If the refractive index of water is 4/3 and the fish is 12cm below the surface,what is the radius of the circle in cm ? (please see attachment for diagram)

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