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A cubical block of glass of refractive index n1 is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of block. After rrefraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle (a) .The valve of (a) is given by?

A cubical block of glass of refractive index n1 is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of block. After rrefraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle (a) .The valve of (a) is given by?
 

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Grade:12

1 Answers

Arun
25758 Points
4 years ago
Dear Rhitvik
 
According to the figure
sin i / sin theta = 1 / n1
For total internal reflection
 
cos i = n2 /n1
 
sin theta = sqrt (n1^2 – n2^2)
 
a = sin^-1[sqrt (n1^2 – n2^2)]
 
 
Regards
Arun (askIITians forum expert)

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