Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

A cubical block of glass of refractive index n1 is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of block. After rrefraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle (a) .The valve of (a) is given by?

A cubical block of glass of refractive index n1 is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of block. After rrefraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle (a) .The valve of (a) is given by?
 

Question Image
Grade:12

1 Answers

Arun
25763 Points
3 years ago
Dear Rhitvik
 
According to the figure
sin i / sin theta = 1 / n1
For total internal reflection
 
cos i = n2 /n1
 
sin theta = sqrt (n1^2 – n2^2)
 
a = sin^-1[sqrt (n1^2 – n2^2)]
 
 
Regards
Arun (askIITians forum expert)

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free